In a parallelogram ABCD, if ∠ DAB=75° and ∠ DBC=60°, then ∠ BDC=

Question

In a parallelogram ABCD, if &#x2220; DAB=75&#xB0; and &#x2220; DBC=60&#xB0;, then &#x2220; BDC=

Philoid · Accepted Answer

We know that,

The opposite angles of a parallelogram are equal

Therefore,

∠BCD = ∠BAD = 75°

Now, in ∆ BCD, we have

∠CDB + ∠DBC + ∠BCD = 180° (Since, sum of the angles of a triangle is 180^o)

∠CDB + 60° + 75° = 180°

∠CDB + 135° = 180°

∠CDB = (180° - 135°) = 45°