Three equal cubes are placed adjacently in a row. The ratio of the total surface area of the resulting cuboid to that of the sum of the surface areas of three cubes, is

Given,


Three equal cubes are placed adjacently in a row


Let edge of cubes = a


Hence , sum of surface area of 3 cubes = 3×6a2 = 18 a2


So, length of cuboid thus formed = a+a+a = 3a


Breadth of cuboid = a


Height of cuboid = a


Total surface area of cuboid =


Hence ,

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