The total surface area of ahollow cylinder which is open from both sides is 4620 sq. cm, area of base ring is 115.5 sq. cm and height 7 cm. Find the thickness of the cylinder.


Given,


Total surface area of hollow cylinder = 4620 cm2


Area of base ring = 115.5 cm2


Height of cylinder = 7 cm


Let outer radius of hollow cylinder = R cm


Let inner radius be = r cm


= πR2 –πr2 = 115.5 ………. (i)


And,


2πrh +2πrh+ 2(πR2 – πr2) = 4620 ……………….(ii)


(putting value of (πR2 – πr2) from (i) to (ii) )


=2πh(R+r) = 4620 -231 = 4389


= π(R+r) =………………..(iii)


From equation (i)


=π(R2 – r2) = 115.5


= π[(R+r)(R-r)] = 115.5


(putting value of π(R+r) from equation (iii))


=


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