The total surface area of ahollow cylinder which is open from both sides is 4620 sq. cm, area of base ring is 115.5 sq. cm and height 7 cm. Find the thickness of the cylinder.
Given,
Total surface area of hollow cylinder = 4620 cm2
Area of base ring = 115.5 cm2
Height of cylinder = 7 cm
Let outer radius of hollow cylinder = R cm
Let inner radius be = r cm
= πR2 –πr2 = 115.5 ………. (i)
And,
2πrh +2πrh+ 2(πR2 – πr2) = 4620 ……………….(ii)
(putting value of (πR2 – πr2) from (i) to (ii) )
=2πh(R+r) = 4620 -231 = 4389
= π(R+r) =………………..(iii)
From equation (i)
=π(R2 – r2) = 115.5
= π[(R+r)(R-r)] = 115.5
(putting value of π(R+r) from equation (iii))
=