A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m. The height of the cylindrical portion is 11 m while the vertex of the cone is 16 m above the ground. Find the area of the canvas required for the tent.
For cylindrical part, we have
Diameter = 24 m so, radius r = 24/2 = 12 m ,
Height = h = 11 m
For conical part, we have
Height of the cone = (16-11) m = 5 m
∴ Slant height =
m = 13 m
Hence, Area of the canvas required
= Curved surface area of cone + Curved surface area of cylinder
= πrl+2πrh=πr(l+2h) = 
×12×(13+22) m2 = 1320 m2
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