A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m. The height of the cylindrical portion is 11 m while the vertex of the cone is 16 m above the ground. Find the area of the canvas required for the tent.

For cylindrical part, we have

Diameter = 24 m so, radius *r* = 24/2 = 12 m ,

Height = *h* = 11 m

For conical part, we have

Height of the cone = (16-11) m = 5 m

∴ Slant height = m = 13 m

Hence, Area of the canvas required

= Curved surface area of cone + Curved surface area of cylinder

= π*rl*+2π*rh*=πr(*l*+2*h*) = ×12×(13+22) m^{2} = 1320 m^{2}

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