A spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. If the diameters of two balls be cm and 2 cm, find the diameter of the third ball.

Question

Philoid · Accepted Answer

Volume of a sphere = (4/3)πr³

Total volume remains same during recasting.

Given, spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls and the diameters of two balls are cm and 2 cm.

Let the diameter of the third ball be ‘a’ cm.

⇒ 27/8 = (27/64) + 1 + (a³/8)

⇒ a³/8 = 125/64

⇒ a³ = 125/8

⇒ a = 5/2 cm