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A spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls. If the diameters of two balls be cm and 2 cm, find the diameter of the third ball.
Volume of a sphere = (4/3)πr3
Total volume remains same during recasting.
Given, spherical ball of lead 3 cm in diameter is melted and recast into three spherical balls and the diameters of two balls are cm and 2 cm.
Let the diameter of the third ball be ‘a’ cm.
⇒ 27/8 = (27/64) + 1 + (a3/8)
⇒ a3/8 = 125/64
⇒ a3 = 125/8
⇒ a = 5/2 cm