A cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm. Find the radius of the ball. (Use π =22/7).

Question

A cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm. Find the radius of the ball. (Use &#x3C0; =22/7).

Philoid · Accepted Answer

Volume of a sphere = (4/3)πr³

Volume of a cylinder = πr²h

Given, a cylindrical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 9 cm.

Volume of water displaced = Volume of the iron ball

⇒ r³ = 1728

⇒ r = 12 cm