A cylinder of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 6.75 cm. Find the radius of the ball (Use π= 22/7)

Question

A cylinder of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 6.75 cm. Find the radius of the ball (Use &#x3C0;= 22/7)

Philoid · Accepted Answer

Volume of a sphere = (4/3)πr³

Volume of a cylinder = πr²h

Given, a cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 6.75 cm.

Volume of water displaced = Volume of the iron ball

⇒ r³ = 729

⇒ r = 9 cm