RD Sharma - Mathematics

Book: RD Sharma - Mathematics

Chapter: 21. Surface Area and Volume of a Sphere

Subject: Mathematics - Class 9th

Q. No. 6 of CCE - Formative Assessment

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6

A cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius. The number of balls will be

Volume of a sphere = (4/3)πr3


Volume of a cylinder = πr2h


Given, cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius.


Let the number of such balls be ‘a’.


π × r2 × 8r = a × (4/3)π × r3


a = 6

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