A cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius. The number of balls will be
Volume of a sphere = (4/3)πr3
Volume of a cylinder = πr2h
Given, cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius.
Let the number of such balls be ‘a’.
⇒ π × r2 × 8r = a × (4/3)π × r3
⇒ a = 6