Construct a ΔABC in which AB+AC=5.6 cm, BC=4.5 cm, and ∠B = 45°.
We are asked to construct a triangle ABC in whichAB+AC=5.6 cm, BC=4.5 cm, and ∠B = 45°, and We will follow the following algorithm for the construction
Steps of construction
STEP1: Draw BC of 4.5 cm.
STEP2: Draw∠B = 45°.
STEP3: From ray BE, cut BD of 5.6 cm.
STEP4: Draw segment DC.
STEP5: Draw the perpendicular bisector of DC, intersecting the ray BE at A
STEP6: Draw segment AC.
ABC is the required triangle.