Construct a ΔABC in which AB+AC=5.6 cm, BC=4.5 cm, and B = 45°.

We are asked to construct a triangle ABC in whichAB+AC=5.6 cm, BC=4.5 cm, and B = 45°, and We will follow the following algorithm for the construction



Steps of construction


STEP1: Draw BC of 4.5 cm.


STEP2: DrawB = 45°.


STEP3: From ray BE, cut BD of 5.6 cm.


STEP4: Draw segment DC.


STEP5: Draw the perpendicular bisector of DC, intersecting the ray BE at A


STEP6: Draw segment AC.


ABC is the required triangle.


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