Find the length of a chord which is at a distance of 5 cm from the centre of a circle of radius 10 cm.

Question

Philoid · Accepted Answer

Given that,

Distance (OC) = 5 cm

Radius of circle (OA) = 10 cm

In by using Pythagoras theorem

AC² + OC² = OA²

AC² + 5² = 10²

AC² = 100 – 25

AC² = 75

AC = 8.66 cm

We know that,

The perpendicular from centre to chord bisects the chord

Therefore,

AC = BC = 8.66 cm

Then,

Chord AB = 8.66 + 8.66

= 17.32 cm