Find the length of a chord which is at a distance of 4 cm from the centre of the circle of radius 6 cm.
Radius of circle (OA) = 6 cm
Distance (OC) = 4 cm
In , by using Pythagoras theorem
AC2 + OC2 = OA2
AC2 + 42 = 62
AC2 = 36 – 16
AC2 = 20
AC = 4.47 cm
We know that,
The perpendicular distance from centre to chord bisects the chord
AC = BC = 4.47 cm
Then,
AB = 4.47 + 4.47
= 8.94 cm