A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find the length of the string of each phone.
Given that,
AB = BC = CA
So, ABC is an equilateral triangle
OA = 40 cm (Radius)
Medians of equilateral triangle pass through the circumference (O) of the equilateral triangle ABC
We also know that,
Median intersects each other at 2: 1 as AD is the median of equilateral triangle ABC, we can write:
=
=
OD = 20 m
Therefore,
AO = OA + OD
= 40 + 20
= 60 m
In
By using Pythagoras theorem
AC2 = AO2 + DC2
AC2 = (60)2 + ()2
AC2 = 3600 +
AC2 = 3600
2 = 4800
m
So, length of string of each phone will be m