A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find the length of the string of each phone.

Given that,

AB = BC = CA


So, ABC is an equilateral triangle


OA = 40 cm (Radius)


Medians of equilateral triangle pass through the circumference (O) of the equilateral triangle ABC


We also know that,


Median intersects each other at 2: 1 as AD is the median of equilateral triangle ABC, we can write:


=


=


OD = 20 m


Therefore,


AO = OA + OD


= 40 + 20


= 60 m


In


By using Pythagoras theorem


AC2 = AO2 + DC2


AC2 = (60)2 + ()2


AC2 = 3600 +


AC2 = 3600


2 = 4800


m


So, length of string of each phone will be m


2