O is the circumcentre of the triangle ANC and OD is perpendicular on BC. Prove that ∠BOD= ∠A
Given that,
O is the circumcentre of triangle ABC and OD perpendicular BC
To prove: ∠BOD = ∠A
Proof: In triangle OBD and triangle OCD, we have
∠ODB = ∠ODC (Each 90o)
OB = OC (Radii)
OD = OD (Common)
By R.H.S rule,
∠BOD = ∠COD (By c.p.c.t) (i)
By degree measure theorem,
∠BOC = 2 ∠BAC
2 ∠BOD = 2 ∠BAC [From (i)]
∠BOD = ∠BAC
Hence, proved