In Fig. 16.177, Δ PQR is an isosceles triangle with PQ=PR and mPQR=35°. Find mQSR and mQTR.

We have,

PQR = 35o


PQR + PRQ = 35o (Angle opposite to equal sides)


In triangle PQR, by angle sum property


P + Q + R = 180o


P + 35o + 35o = 180o


P = 110o


Now,


QSR + QTR = 180o


110o + QTR = 180o


QTR = 70o


2