In Fig. 16.181, O is the centre of the circle. Find CBD.

Given that,

BOC = 100o


By degree measure theorem,


AOC = 2 APC


100o = 2 APC


APC = 50o


Therefore,


APC + ABC = 180o (Opposite angles of a cyclic quadrilateral)


50o + ABC = 180o


ABC = 130o


Therefore,


ABC + CBD = 180o (Linear pair)


130o + CBD = 180o


CBD = 50o


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