On a semi-circle with AB as diameter, a point C is taken, so that m(∠CAB)= 30°. Find m(∠ACB) and m(∠ABC).
We have,
∠CAB = 30o
∠ACB = 90o (Angle in semi-circle)
IN triangle ABC, by angle sum property
∠CAB + ∠ACB + ∠ABC = 180o
30o + 90o + ∠ABC = 180o
∠ABC = 60o