On a semi-circle with AB as diameter, a point C is taken, so that m(CAB)= 30°. Find m(ACB) and m(ABC).

We have,

CAB = 30o


ACB = 90o (Angle in semi-circle)


IN triangle ABC, by angle sum property


CAB + ACB + ABC = 180o


30o + 90o + ABC = 180o


ABC = 60o


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