In a cyclic quadrilateral ABCD if AB||CD and B=70°, find the remaining angles.
Given that,
∠B = 70o
Since, ABCD is a cyclic quadrilateral
Then,
∠B + ∠D = 180o
70o + ∠D = 180o
∠D = 110o
Since, AB ‖ DC
Then,
∠B + ∠C = 180o (Co. interior angle)
70o + ∠C = 180o
∠C = 110o
Now,
∠A + ∠C = 180o (Opposite angles of cyclic quadrilateral)
∠A + 110o = 180o
∠A = 70o