In a cyclic quadrilateral ABCD if AB||CD and B=70°, find the remaining angles.

Given that,

B = 70o


Since, ABCD is a cyclic quadrilateral


Then,


B + D = 180o


70o + D = 180o


D = 110o


Since, AB DC


Then,


B + C = 180o (Co. interior angle)


70o + C = 180o


C = 110o


Now,


A + C = 180o (Opposite angles of cyclic quadrilateral)


A + 110o = 180o


A = 70o


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