In a cyclic quadrilateral ABCD, if m ∠A =3(m∠C). Find m∠A.
WE have,
∠A = 3 ∠C
Let, ∠C = x
Therefore,
∠A + ∠C = 180o (Opposite angles of cyclic quadrilateral)
3x + x = 180o
4x = 180o
x = 45o
∠A = 3x
= 3 * 45o
= 135o
∠A = 135o