In a cyclic quadrilateral ABCD, if m A =3(mC). Find mA.

WE have,

A = 3 C


Let, C = x


Therefore,


A + C = 180o (Opposite angles of cyclic quadrilateral)


3x + x = 180o


4x = 180o


x = 45o


A = 3x


= 3 * 45o


= 135o


Therefore,


A = 135o


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