Prove that the angle in a segment shorter than a semicircle is greater than a right angle.

Given that,

ACB is an angle in minor segment


To prove: ACB > 90o


Proof: By degree measure theorem


Reflex AOB = 2 ACB


And,


Reflex AOB > 180o


Then,


2 ACB > 180o


ACB >


ACB > 90o


Hence, proved


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