Prove that the angle in a segment shorter than a semicircle is greater than a right angle.
Given that,
∠ACB is an angle in minor segment
To prove: ∠ACB > 90o
Proof: By degree measure theorem
Reflex ∠AOB = 2 ∠ACB
And,
Reflex ∠AOB > 180o
Then,
2 ∠ACB > 180o
∠ACB >
∠ACB > 90o
Hence, proved