ABCD is a cyclic trapezium with AD||BC. If ∠B=70°, determine other three angles of the trapezium.
Given that,
ABCD is a cyclic trapezium with AD ‖ BC and ∠B = 70o
Since, ABCD is a quadrilateral
Then,
∠B + ∠D = 180o
70o + ∠D = 180o
∠D = 110o
Since, AD ‖ BC
Then,
∠A + ∠B = 180o (Co. interior angle)
∠A + 70o = 180o
∠A = 110o
Since, ABCD is a cyclic quadrilateral
Then, ∠A + ∠C = 180o
110o + ∠C = 180o
∠C = 70o