ABCD is a cyclic trapezium with AD||BC. If B=70°, determine other three angles of the trapezium.

Given that,

ABCD is a cyclic trapezium with AD BC and B = 70o


Since, ABCD is a quadrilateral


Then,


B + D = 180o


70o + D = 180o


D = 110o


Since, AD BC


Then,


A + B = 180o (Co. interior angle)


A + 70o = 180o


A = 110o


Since, ABCD is a cyclic quadrilateral


Then, A + C = 180o


110o + C = 180o


C = 70o


27