In Fig. 16.189, ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If DBC=55° and BAC=45°, find BCD.

Since angles on the same segment of a circle are equal

Therefore,


CAD = DBC = 55o


DAB = CAD + BAC


= 55o + 45o


= 100o


But,


DAB + BCD = 180o (Opposite angles of a cyclic quadrilateral)


Therefore,


BCD = 180o – 100o


BCD = 80o


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