In Fig. 16.194, two congruent circles with centres O and O’ intersect at A and B. If ∠AO’B=50°, then find ∠APB.
∠AO'B = 50o
Since, both the triangle are congruent so their corresponding angles are equal.
∠AOB = AO'B = 50°
Now,
∠APB =
= 25°