In Fig. 16.196, if O is the circumcentre of Δ ABC, then find the value of ∠OBC + ∠BAC.
∠OBC + ∠CBA = ∠OBA
∠OBC + 30° = 50°
∠OBC = 20°
∠OBC + ∠BAC = ∠OBC + ∠CAB
= 20° + 110°
= 130°