In Fig. 16.200, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, ∠BQD=

Question

In Fig. 16.200, P and Q are centres of two circles intersecting at B and C. ACD is a straight line. Then, &#x2220; BQD =

Philoid · Accepted Answer

We know that,

∠ACB =

∠ACB = 75^o

Since,

ACD is a straight line, so

∠ACB + ∠BCD = 180^o

75^o + ∠BCD = 180^o

∠BCD = 180^o – 75^o

= 105^o

Now,

∠BCD = Reflex ∠BQD

105^o = (360^o - ∠BQD)

210^o = 360^o - ∠BQD

∠BQD = 360^o – 210^o

Therefore,

∠BQD = 150^o