The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length, is
Let, O be the centre of the circle with chord AB = 8cm
And,
OC be the perpendicular bisector of AC
AO = 6cm
AC = 4cm
In AOC,
OA2 = AC2 + OC2
62 = 42 + OC2
OC2 = 20
OC = 25