ABCD is a cyclic quadrilateral such that ∠ADB =30° and ∠DCA =80°, then ∠DAB =
ABCD is a cyclic quadrilateral
∠ADB = 30°
∠DCA = 80°
∠ADB = ∠ACB = 30° (Angle on the same segment)
Now,
∠BCD = ∠ACB + ∠DCA
= 30° + 80°
= 110°
∠OAB + ∠BCD = 180°
∠OAB + 110° = 180°
∠OAB = 70°