A chord of length 14 cm is at a distance of 6 cm from the centre of a circle. The length of another chord at a distance of 2 cm from the centre of the circle is
Let AB and CD be two chords of the circle.
Draw OM perpendicular to AB and ON = CD
AB = 14 cm
OM = 6 cm
ON = 2 cm
Let,
CD = x
In AOM,
AO2 = AM2 + OM2
= 72 + 62
AO2 = 85 (i)
In CON,
CO2 = ON2 + CN2
CO2 = 4 + (ii)
We Know,
AO = CO
AO2 = CO2
85 = 4 +
x2 = 324
x = 18 cm