A chord of length 14 cm is at a distance of 6 cm from the centre of a circle. The length of another chord at a distance of 2 cm from the centre of the circle is

Let AB and CD be two chords of the circle.

Draw OM perpendicular to AB and ON = CD


AB = 14 cm


OM = 6 cm


ON = 2 cm


Let,


CD = x


In AOM,


AO2 = AM2 + OM2


= 72 + 62


AO2 = 85 (i)


In CON,


CO2 = ON2 + CN2


CO2 = 4 + (ii)


We Know,


AO = CO


AO2 = CO2


85 = 4 +


x2 = 324


x = 18 cm

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