The chord of a circle is equal to its radius. The angle substended by this chord at the minor arc of the circle is

Question

Philoid · Accepted Answer

Let AB be the chord of circle equal to radius r

OA = OB = r (Radii)

Therefore,

OA = OB = AB

OBC is equilateral triangle

Each angle = 60°

Hence,

Angle surrounded by AB at minor arc = (Reflex * ∠AOD)

= (360^o – 60^o)

= 150^o