In Fig. 16.205, chords AD and BC intersect each other at right angles at a point P. If ∠DAB=35°, then ∠ADC=
Given that,
Chords AD and BC intersect at right angles,
∠DAB = 35°
∠APC = 90°
∠APC + ∠CPD = 180°
90o + ∠CPD = 180°
∠CPD = 90°
∠DAB = ∠PCD = 35° (Angles on the same segment)
In triangle PCD,
∠PCD + ∠PDC + ∠CPD = 180°
35° + ∠PDC + 90° = 180°
∠PDC = 45°
∠ADC = 45°