In Fig. 16.205, chords AD and BC intersect each other at right angles at a point P. If DAB=35°, then ADC=

Given that,

Chords AD and BC intersect at right angles,


DAB = 35°


APC = 90°


APC + CPD = 180°


90o + CPD = 180°


CPD = 90°


DAB = PCD = 35° (Angles on the same segment)


In triangle PCD,


PCD + PDC + CPD = 180°


35° + PDC + 90° = 180°


PDC = 45°


ADC = 45°

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