Draw the graphs of the following linear equations on the same graph paper.
2x+3y = 12, x – y = 1
Find the coordinates of the vertices of the triangle formed by the two straight lines and the y-axis. Also, find the area of the triangle.
X-Y=1
2x + 3y =12
2x + 3y = 12 passes through (6, 0) and (0, 4)
x – y = 1 passes through (1, 0) and (0, -1)
Coordinates of the vertices of the triangle formed with the y axis are (0, 4), (0, -1) and (3, 2)
Base of the triangle = 4 + 1 =
Height of the triangle = 3
Area of the triangle
⇒ Area of the triangle