The path of a train A is given by the equation 3x+4y-12=0 and the path of another train B is given by the equation 6x+8y-48=0. Represent this situation graphically.

Given, path of a train A is given by the equation 3x+4y-12=0 and the path of another train B is given by the equation 6x+8y-48=0.



3x + 4y – 12 = 0 passes through (4, 0) and (0, 3)


6x + 8y – 48 = 0 passes through (8, 0) and (0, 6)


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