If the graph of the equation 4x+3y=12 cuts the coordinate axes at A and B, then hypotenuse of right triangle AOB is of length
4x + 3y = 12
A is (3, 0)
B is (0, 4)
Base of triangle AOB = OA = 3 untis
Perpendicualr of triangle AOB = OB = 4 units
Hypotenuse2 = perepndicular2 + base2
⇒ Hypotenuse2 = 16 + 9 = 25 sq units
⇒ Hypotenuse = 5 units