AB is a chord of a circle with centre O and radius 4cm. AB is of length 4cm and divides the circle into two segments. Find the area of the minor segment.


Given,


Radius of circle = 4cm


Length of chord = 4cm


(Hence it makes an equilateral triangle at centre, in which all angle must be = 60°)


Area of sector =




Area of ∆OAB =


Area of minor segment = area of sector – area of ∆OAB



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