Without performing actual computations, find the quotient when 94-49 is divided by

(i) 9 (ii) 5

1) Here, we observe that 94 and 49 are having ten’s and unit place interchanged, ie they are having reverse digits.


Hence, difference of digits is 5.


We know that when ab – ba is divided by 9, the quotient is (a – b).


94 49 is divided by 9, the quotient is 5.


2) Here, we observe that 94 and 49 are having ten’s and unit place interchanged, ie they are having reverse digits.


Hence, difference of digits is 5.


We know that when ab – ba is divided by (a – b), quotient is 9.


the difference of 94 and 49 is divided by 5 (difference of digits) , we get 9 as our quotient.


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