If x is a digit of the number such that it is divisible by 9, find possible values of x.

Here it is given that is divisible by 9.


We know that if a number is divisible by 9, then sum of digits must be a multiple of 9.


6 + 6+7+8+4 + x = multiple of 9


x + 31 = 0,9,18,27,…..


But ‘x’ is a digit, hence, ‘x’ can have value between 0 to 9.


x + 31 = 36.


x = 5


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