Solved each of the following Cryptarithms:
For unit’s place,
We have two conditions, when 7 + B ≤ 9 and 7 + B > 9
For 7 + B ≤ 9
7 + B = A
∴ A – B = 7 …(1)
In ten’ place,
B + A = 8 …(2)
Solving 1 and 2 simultaneously,
2A = 15 which means A = 7.5 which is not possible
Hence, our condition 7 + B ≤ 9 is wrong.
∴ 7 + B > 9 is correct condition
Hence, carrying one in ten’s place and subtracting 10 from unit’s place,
7 + B – 10 = A
∴ B – A = 3 … (3)
For ten’s place,
B + A + 1 = 8
∴ B + A =7 …(4)
Solving 3 and 4 simultaneously,
2B = 10
∴ B = 5 and A = 2