Observe the following pattern
And find the value of
(i) 1002-992 (ii) 1112-1092
(iii)992-962
(i) 1002 – 992
= 100 + 99
= 199
(ii) 1112 - 1092
= 1112 – 1102 + 1102 - 1092
= (111 + 110) + (110 + 109)
= 440
(iii) 992 - 962
= 992 – 982 + 982 – 972 + 972 - 962
= (99 + 98) + (98 + 92) + (97 + 96)
= 585
6