Observe the following pattern
And find the values of each of the following:
(i) 1+2+3+4+5+……….+50
(ii) 31+32+……..+50
R.H.S = [No. of terms in L.H.S × (No. of terms + 1)] (Therefore, only when L.H.S starts with 1)
Therefore,
(i) 1 + 2 + 3 +…..50 = [50 × (50 + 1)]
= 25 × 51
= 1275
(ii) 31 + 32 +…..+50 = (1 + 2 + 3 + …. + 50) – (1 + 2 + ….. 30)
= 1275 – [ (30 × 30 +1)]
= 1275 – 465
= 810