Observe the following pattern



And find the values of each of the following:


(i) 1+2+3+4+5+……….+50


(ii) 31+32+……..+50

R.H.S = [No. of terms in L.H.S × (No. of terms + 1)] (Therefore, only when L.H.S starts with 1)

Therefore,

(i) 1 + 2 + 3 +…..50 = [50 × (50 + 1)]

= 25 × 51

= 1275

(ii) 31 + 32 +…..+50 = (1 + 2 + 3 + …. + 50) – (1 + 2 + ….. 30)

= 1275 – [ (30 × 30 +1)]

= 1275 – 465

= 810

9