Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when (i) A coincides with the origin and AB and AD are along OX and OY respectively. (ii) The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.

Question

Philoid · Accepted Answer

(i) Since each side of square is 2a.

Coordinates of A are (0, 0), since it coincides with origin.

Coordinates of B are (2a, 0), for a point along x-axis ordinate is zero.

Coordinates of C are (2a, 2a), since this point is equi-distance from x-axis and y-axis.

Coordinates of D are (0, 2a), since abscissa is zero and ordinate is 2a.

(ii) Each side of square is a units.

Coordinates of A are (a, a), since this point lies in Ist coordinate.

Coordinates of B are (-a, a), since this point lies in IInd coordinate.

Coordinates of C are (-a, -a), since this point lies in IIIrd coordinate.

Coordinates of D are (a, -a), since this point lies in IVth coordinate.

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when(i) A coincides with the origin and AB and AD are along OX and OY respectively.(ii) The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.

Let ABCD be a square of side 2a. Find the coordinates of the vertices of this square when
(i) A coincides with the origin and AB and AD are along OX and OY respectively.

(ii) The centre of the square is at the origin and coordinate axes are parallel to the sides AB and AD respectively.