The base PQ of two equilateral triangles PQR and PQR' with side 2a lies along y-axis such that the mid-point of PQ is at the origin. Find the coordinates of the vertices R and R' of the triangles.


Since PQ is the base of two equilateral triangles with side 2a and mid-point of PQ is at origin.


Therefore point R lies on positive x-axis and point R’ lies on negative y-axis.


OR2 = (2a)2- a2


OR2 = 4a2- a2


OR = √3a


Therefore coordinates of R are ( √3a, 0) and R’ (0, √3a)


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