Two vertices of an isosceles triangle are (2, 0) and (2, 5). Find the third vertex if the length of the equal sides is 3.

Vertices of an isosceles are: A(2, 0) and B(2, 5).


Let the third vertex is P(x, y)


Using distance formula =


Length of side PA = units


Length of side PB = units


Since PA = PB



On squaring both sides, we get




,


Also, PA = 3



On squaring both sides, we get





On substituting ,





Using quadratic formula:





Therefore coordinates of third vertex are: ;


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