Find the centre of the circle passing through (2, 1), (5, - 8) and (2, - 9).

Coordinates of points on a circle are A(2,1), B(5,-8) and C(2,-9).


Let the coordinates of the centre of the circle be O(x, y)


Using distance formula =


Since the distance of the points A, B and C will be equal from the center, therefore


OA = OB



On squaring both sides, we get


x2 + 4 - 4x + y2 + 1 - 2y = x2 + 25 - 10x + y2 + 64 + 16y


6x - 18y - 84 = 0


x - 3y - 14 = 0 ------------- (1)


Similarly, OC = OB


x2 + 4 - 4x + y2 + 81 + 18y = x2 + 25 - 10x + y2 + 64 + 16y


6x - 2y - 4 = 0


3x - y - 2 = 0 ------------- (2)


By solving equations (1) and (2), we get x = -1, y = -5


So, the coordinates of the centre of the circle is (-1, -5).


Radius of the circle = OA =


=


=


= units


23