Find the value of x such that where the coordinates of P, Q and R are (6,-1), (1, 3) and (x, 8) respectively.
Coordinates are P(6,-1), Q(1, 3) and R(x, 8)
Using distance formula =
⇒ PQ = QR
On squaring both sides, we get
=
=
On solving above equation, we get
Therefore x = -3, 5