Find the value of x such that where the coordinates of P, Q and R are (6,-1), (1, 3) and (x, 8) respectively.

Coordinates are P(6,-1), Q(1, 3) and R(x, 8)


Using distance formula =


PQ = QR



On squaring both sides, we get


=


=



On solving above equation, we get







Therefore x = -3, 5


31