If the point P (k -1, 2) is equidistant from the points A (3, k) and B (k,5), find the value of k.
Coordinates of points are A(3, k), B(k, 5) and P(k-1, 2)
Using distance formula =
⇒ PA = PB
On squaring both sides, we get
=
=
= 1 + 9
= 0
= 0
= 0
= 0
= 1, 5