Find the points of trisection of the line segment joining the points:

(i) (5, -6) and (- 7, 5), (ii) (3, -2) and (-3, -4), (iii) (2, -2) and (-7, 4)

(i) (5, -6) and (- 7, 5),


Let our given points be A(5,-6) and B(-7, 5) and required points be C (x1 , y1 ) and D(x2 , y2)


The points of trisection of a line are points which divide into the ratio 1:2



By section formula,


x = , y =


For point C(x1 , y1 )


x1 = , y1= …Here m = 1 and n = 2


x1 = , y1 =


C (x1 , y1 ) ≡ (1, )


For point D(x2 , y2 )


X2 = , y2= …Here m = 2 and n = 1


x2 = , y2 =


D (x2 , y2)≡ (-3, )


Hence, the points of trisection of line joining given points are (1, ) and (-3, )


(ii) (3, -2) and (-3, -4)


Let our given points be A(3,-2) and B(-3, -4) and required points be C (x1 , y1 ) and D(x2 , y2)


The points of trisection of a line are points which divide into the ratio 1:2



By section formula,


x = , y =


For point C(x1 , y1 )


x1 = , y1= …Here m = 1 and n = 2


x1 = , y1 =


C (x1 , y1 ) ≡ ( , )


For point D(x2 , y2 )


X2 = , y2= …Here m = 2 and n = 1


x2 = , y2 =


D (x2 , y2)≡ (-1, )


Hence, the points of trisection of line joining given points are ( , ) and (-1, )


(iii) (2, -2) and (-7, 4)


Let our given points be A(2,-2) and B(-7, 4) and required points be C (x1 , y1 ) and D(x2 , y2)


The points of trisection of a line are points which divide into the ratio 1:2



By section formula,


x = , y =


For point C(x1 , y1 )


x1 = , y1= …Here m = 1 and n = 2


x1 = , y1 =


C (x1 , y1 ) ≡ ( , )


For point D(x2 , y2 )


X2 = , y2= …Here m = 2 and n = 1


x2 = , y2 =


D (x2 , y2)≡ (-4, 2)


2