Find the coordinates of the point where the diagonals of the parallelogram formed by joining the points (-2, -1), (1, 0), (4, 3) and (1, 2) meet.

Let our points of parallelogram be A(-2, -1), B(1, 0), C(4, 3) and D(1, 2) and mid point of diagonals be E(x,y)



We know that diagonals of parallelogram bisect each other.


Hence, we find mid point of AC.


By midpoint formula,


x = , y =


For point E(x, y)


x1 = , y1=


x1 = , y1 =


E (x, y) ≡ ( , 1 )


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