Prove that the points (3, -2), (4, 0), (6, -3) and (5, -5) are the vertices of a parallelogram.

We know if the quadrilateral is parallelogram if opposite sides are equal.


Let our points be A(3, -2), B(4, 0), C(6, -3) and D(5, -5).



By distance formula,


XY =


For AB,


AB =


=


= units


For BC,


BC =


=


= units


For CD,


CD =


=


= units


For AD,


AD =


=


= units


Here, we observe that AB = CD and AD = BC, which means that the quadrilateral formed by lines joining by points, is parallelogram.


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