If the mid-point of the line joining (3, 4) and (k, 7) is (x, y) and 2x + 2y + 1 = 0, find the value of k.

Let A(3, 4) and B(k, 7) and midpoint be C(x, y) which lies on the line 2x+2y+1 = 0



By midpoint formula,


x = , y =


For point C(x, y),


x = , y = …(1)


Here, y = ,


Hence, substituting value of y in given equation of line,


2x + 2 × + 1 = 0


∴ 2x = -12


∴ x = -6


Now substituting value of x in equation(1), we get.


x =


-6 =


∴ -12 = 3 + k


∴ k = -15


Hence, the value of k is -15.

12