Three vertices of a parallelogram are (a + b, a - b), (2a + b, 2a - b), (a - b, a + b). Find the fourth vertex.

Let A(a + b, a - b), B(2a + b, 2a - b), C(a - b, a + b) and fourth vertex be D(x, y).



It is given that □ABCD is parallelogram.


We know that diagonals of parallelogram bisect each other.


Let intersection of diagonals be E(xm, ym )


By midpoint formula.


xm = , ym =


For midpoint E of diagonal AC,


xm = , ym =


xm = a , ym = a


E(xm, ym ) ≡ (a, a)


For diagonal BD,


a = , a=


2a = 2a + b +x , 2a = 2a – b +y


x = -b and y = b


Hence, the fourth vertex is D(-b, b)


19