ABCD is a rectangle formed by joining the points A (-1, -1), B (-1, 4), C (5, 4) and D (5,-1). P, Q, R and S are the mid-points of sides AB, BC, CD and DA respectively. Is the quadrilateral PQRS a square? a rectangle? or a rhombus? Justify your answer.

Here given that A (-1, -1), B (-1, 4), C (5, 4) and D (5,-1).Also P, Q, R and S are the mid-points of sides AB, BC, CD and DA respectively.



By midpoint formula.


x = , y =


For midpoint P of side AB,


x = , y =


x = -1 , y =


Hence, the coordinates of P are (-1 , )


For midpoint Q of side BC,


x = , y =


x = 2 , y = 4


Hence, the coordinates of Q are (2 ,4)


For midpoint R of side CD,


x = , y =


x = 5 , y =


Hence, the coordinates of R are (5 , )


For midpoint S of side AD,


x = , y =


x = 2 , y = -1


Hence, the coordinates of S are (2 ,-1)


Now we find length of the length of the □PQRS,


By distance formula,


XY =


For PQ,


PQ =


=


= units


For QR,


QR =


=


= units


For RS,


RS =


=


= units


For PS,


PS =


=


= units


Here we can observe that all lengths of □PQRS are equal.


Now for diagonal PR,


PR =


=


= units


Now for diagonal QS,


QS =


=


= 5 units


Here in □PQRS, diagonals are unequal.


We know that a quadrilateral whose all sides are equal and diagonals are unequal, it is a rhombus.


Hence, our □PQRS is rhombus .


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